Q
What keyword is used to declare a block-scoped variable in ES6?

Answer & Solution

Answer: Option B
Solution:
The let keyword allows you to declare variables that are limited to the scope of a block statement.
Related Questions on Average

What is the result of [...['a', 'b', 'c']]?

A). ['a', 'b', 'c']

B). [['a', 'b', 'c']]

C). ['abc']

D). Error

What is the correct syntax to create a class in ES6?

A). class MyClass {}

B). class = MyClass {}

C). new MyClass = class {}

D). create class MyClass {}

What is the output of const [a, b] = [1, 2];?

A). a = 1, b = 2

B). a = [1], b = [2]

C). a = 2, b = 1

D). Error

What does the ... operator do when used in a function parameter?

A). It spreads an array

B). It restates the parameters

C). It indicates a default parameter

D). It represents the rest of the arguments

How do you create a generator function in ES6?

A). function* gen() {}

B). function gen*() {}

C). function*gen() {}

D). function * gen() {}

How do you export a function in ES6 modules?

A). export function myFunc() {}

B). module.exports = myFunc;

C). exports.myFunc = function() {}

D). export myFunc = function() {}

What does the method Array.from() do?

A). Converts an array to a string

B). Converts an iterable or array-like object to an array

C). Clones an array

D). Filters an array

What is the output of [...'hello']?

A). ['hello']

B). ['h', 'e', 'l', 'l', 'o']

C). [104, 101, 108, 108, 111]

D). ['h', 'e', 'll', 'o']

What is the output of typeof Symbol('description')?

A). 'string'

B). 'object'

C). 'symbol'

D). 'undefined'

What is the syntax for an arrow function in ES6?

A). function(a, b) { return a + b; }

B). (a, b) => { return a + b; }

C). (a, b) => a + b

D). Both B and C