Q
What keyword is used to declare a block-scoped variable in ES6?

Answer & Solution

Answer: Option B
Solution:
The let keyword allows you to declare variables that are limited to the scope of a block statement.
Related Questions on Average

What does the ... operator do when used in a function parameter?

A). It spreads an array

B). It restates the parameters

C). It indicates a default parameter

D). It represents the rest of the arguments

What is the output of typeof Symbol('description')?

A). 'string'

B). 'object'

C). 'symbol'

D). 'undefined'

What does the method Array.from() do?

A). Converts an array to a string

B). Converts an iterable or array-like object to an array

C). Clones an array

D). Filters an array

How can you create a new promise in ES6?

A). new Promise(function)

B). Promise(function)

C). promise(function)

D). New Promise(function)

What is the output of const [a, b] = [1, 2];?

A). a = 1, b = 2

B). a = [1], b = [2]

C). a = 2, b = 1

D). Error

How do you define a default parameter in a function?

A). function(a, b = 2) {}

B). function(a, b: 2) {}

C). function(a, b = [2]) {}

D). function(a, b := 2) {}

How do you check if a value is an array in ES6?

A). Array.isArray(value)

B). value.isArray()

C). value instanceof Array

D). typeof value === 'array'

What does the for...of loop iterate over?

A). Object properties

B). Object values

C). Array indices

D). Iterable objects

What does Promise.resolve(5).then(console.log) print?

A). 5

B). undefined

C). null

D). Error

What is the result of [...['a', 'b', 'c']]?

A). ['a', 'b', 'c']

B). [['a', 'b', 'c']]

C). ['abc']

D). Error