Q
What does the ... operator do when used in a function parameter?

Answer & Solution

Answer: Option D
Solution:
The rest operator (...) represents an indefinite number of arguments as an array.
Related Questions on Average

How can you create a new promise in ES6?

A). new Promise(function)

B). Promise(function)

C). promise(function)

D). New Promise(function)

What is the syntax for an arrow function in ES6?

A). function(a, b) { return a + b; }

B). (a, b) => { return a + b; }

C). (a, b) => a + b

D). Both B and C

How do you import a default export in ES6?

A). import { myFunc } from 'module';

B). import myFunc from 'module';

C). import * as myFunc from 'module';

D). import { default as myFunc } from 'module';

How do you export a function in ES6 modules?

A). export function myFunc() {}

B). module.exports = myFunc;

C). exports.myFunc = function() {}

D). export myFunc = function() {}

What is the correct syntax to create a class in ES6?

A). class MyClass {}

B). class = MyClass {}

C). new MyClass = class {}

D). create class MyClass {}

What does Promise.resolve(5).then(console.log) print?

A). 5

B). undefined

C). null

D). Error

What does the for...of loop iterate over?

A). Object properties

B). Object values

C). Array indices

D). Iterable objects

What keyword is used to declare a block-scoped variable in ES6?

A). var

B). let

C). const

D). function

How do you check if a value is an array in ES6?

A). Array.isArray(value)

B). value.isArray()

C). value instanceof Array

D). typeof value === 'array'

How do you interpolate variables in a string using template literals?

A). Hello, + name + '!'

B). Hello, ${name}!

C). 'Hello, ' + name + '!'

D). Both A and B