Q
How do you declare a constant variable in ES6?

Answer & Solution

Answer: Option A
Solution:
The const keyword is used to declare variables that are read-only and block-scoped.
Related Questions on Average

What does the for...of loop iterate over?

A). Object properties

B). Object values

C). Array indices

D). Iterable objects

What does the ... operator do when used in a function parameter?

A). It spreads an array

B). It restates the parameters

C). It indicates a default parameter

D). It represents the rest of the arguments

What is the output of const [a, b] = [1, 2];?

A). a = 1, b = 2

B). a = [1], b = [2]

C). a = 2, b = 1

D). Error

How do you export a function in ES6 modules?

A). export function myFunc() {}

B). module.exports = myFunc;

C). exports.myFunc = function() {}

D). export myFunc = function() {}

How do you create a generator function in ES6?

A). function* gen() {}

B). function gen*() {}

C). function*gen() {}

D). function * gen() {}

How can you create a new promise in ES6?

A). new Promise(function)

B). Promise(function)

C). promise(function)

D). New Promise(function)

What keyword is used to declare a block-scoped variable in ES6?

A). var

B). let

C). const

D). function

How do you define a default parameter in a function?

A). function(a, b = 2) {}

B). function(a, b: 2) {}

C). function(a, b = [2]) {}

D). function(a, b := 2) {}

How do you check if a value is an array in ES6?

A). Array.isArray(value)

B). value.isArray()

C). value instanceof Array

D). typeof value === 'array'

What is the syntax for an arrow function in ES6?

A). function(a, b) { return a + b; }

B). (a, b) => { return a + b; }

C). (a, b) => a + b

D). Both B and C