Q
What is the output of [...'hello']?

Answer & Solution

Answer: Option B
Solution:
The spread operator splits a string into an array of characters.
Related Questions on Average

How do you create a generator function in ES6?

A). function* gen() {}

B). function gen*() {}

C). function*gen() {}

D). function * gen() {}

What is the output of const [a, b] = [1, 2];?

A). a = 1, b = 2

B). a = [1], b = [2]

C). a = 2, b = 1

D). Error

How do you interpolate variables in a string using template literals?

A). Hello, + name + '!'

B). Hello, ${name}!

C). 'Hello, ' + name + '!'

D). Both A and B

What does the ... operator do when used in a function parameter?

A). It spreads an array

B). It restates the parameters

C). It indicates a default parameter

D). It represents the rest of the arguments

What does the method Array.from() do?

A). Converts an array to a string

B). Converts an iterable or array-like object to an array

C). Clones an array

D). Filters an array

What is the correct syntax to create a class in ES6?

A). class MyClass {}

B). class = MyClass {}

C). new MyClass = class {}

D). create class MyClass {}

How do you import a default export in ES6?

A). import { myFunc } from 'module';

B). import myFunc from 'module';

C). import * as myFunc from 'module';

D). import { default as myFunc } from 'module';

How do you define a default parameter in a function?

A). function(a, b = 2) {}

B). function(a, b: 2) {}

C). function(a, b = [2]) {}

D). function(a, b := 2) {}

What does Promise.resolve(5).then(console.log) print?

A). 5

B). undefined

C). null

D). Error

How do you export a function in ES6 modules?

A). export function myFunc() {}

B). module.exports = myFunc;

C). exports.myFunc = function() {}

D). export myFunc = function() {}