What is the significance of passing functions as arguments in PHP?
A). It allows functions to be called multiple times
B). It simplifies the function definition process
C). It enables dynamic function invocation and behavior
D). It prevents code duplication
What will be the output of the following PHP code?<?php
$greet = function($name) {
return 'Hello, $name!';
};
echo $greet('John');
?>
A). Hello, John!
B). Hello, $name!
C). function($name) {
return 'Hello, $name!';
}
D). John
How do you define parameters in a PHP function?
A). Parameters are defined within parentheses after the function name
B). Parameters are defined using the keyword 'param'
C). Parameters are defined using curly braces {}
D). Parameters are defined using square brackets []
What is the purpose of parameters in PHP functions?
A). To store values within the function
B). To define the return type of the function
C). To specify values that are passed to the function when it is called
D). To specify the visibility of the function
What will be the output of the following PHP code?<?php
function outer() {
function inner() {
echo 'Inner function';
}
}
inner();
?>
A). Inner function
B). Function does not exist: inner
C). Undefined function: inner
D). Function inner() { echo 'Inner function'; }
Which of the following statements is true about function names in PHP?
A). Function names are case-sensitive
B). Function names must start with a dollar sign ($)
C). Function names cannot contain numbers
D). Function names can contain spaces
What is the output of the following PHP code?<?php
$num = 10;
function testScope() {
global $num;
echo $num;
}
testScope();
?>
A). 10
B). 0
C). Undefined variable: num
D). Variable $num cannot be accessed outside the function
Which of the following statements about return types in PHP functions is true?
A). PHP functions must always have a return type
B). PHP functions can have a return type specified using the 'returns' keyword
C). PHP functions can have a return type specified using the 'return' keyword
D). PHP functions can have a return type declared using type declarations
What is the output of the following PHP code?<?php
function greet() {
echo 'Hello, World!';
}
if (function_exists('greet')) {
greet();
} else {
echo 'Function does not exist';
}
?>
A). Hello, World!
B). Function does not exist
C). Undefined function: greet
D). Function greet() { echo 'Hello, World!'; }
What is the purpose of the return statement in PHP functions?
A). To terminate the function execution
B). To output a value from the function and terminate its execution
C). To define the function name
D). To declare a variable within the function