Q
What is the output of the following PHP code?

<?php
$num = 10;
function testScope() {
global $num;
echo $num;
}
testScope();
?>

Answer & Solution

Answer: Option A
Solution:
The output of the code will be 10 because the $num variable is declared as global inside the testScope() function using the global keyword, allowing it to access the global variable with the same name declared outside the function.
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