Q
What will be the output of the following code? let name = 'Alice'; let Name = 'Bob'; console.log(name, Name);

Answer & Solution

Answer: Option A
Solution:
The output will be 'Alice Bob' because 'name' and 'Name' are different variables.
Related Questions on Average

What is the effect of case sensitivity on debugging JavaScript code?

A). No effect

B). Makes it easier

C). Makes it harder

D). No significant impact

How does JavaScript differentiate between 'myVar' and 'MyVar'?

A). It doesn't, both are the same

B). It treats them as different variables

C). It throws an error

D). None of the above

How will JavaScript handle 'VarName' and 'varName' in the same scope?

A). Treat as the same

B). Treat as different

C). Throw an error

D). Ignore one

What is the best practice for naming variables to avoid issues with case sensitivity?

A). Use only lowercase

B). Use only UPPERCASE

C). Use consistent case conventions

D). Use special characters

What happens if you try to declare two variables with the same name but different cases?

A). Error

B). Both are declared

C). Only one is declared

D). None of the above

Is 'myfunction' the same as 'myFunction' in JavaScript?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

How should constants be declared to avoid confusion with variable names?

A). UPPERCASE

B). lowercase

C). camelCase

D). snake_case

How does JavaScript treat 'Function()' and 'function()'?

A). As the same function

B). As different functions

C). As a syntax error

D). As a reserved keyword

Can JavaScript variables 'example' and 'Example' be declared in the same scope?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

How does JavaScript interpret the following? let varName = 5; let VarName = 10; console.log(varName, VarName);

A). 5 5

B). 10 10

C). 5 10

D). 10 5