Q
What will be the output of the following code? let name = 'Alice'; let Name = 'Bob'; console.log(name, Name);

Answer & Solution

Answer: Option A
Solution:
The output will be 'Alice Bob' because 'name' and 'Name' are different variables.
Related Questions on Average

In JavaScript, is 'myVariable' the same as 'myvariable'?

A). Yes

B). No

C). Depends on the context

D). Only in strict mode

How does JavaScript interpret the following? let varName = 5; let VarName = 10; console.log(varName, VarName);

A). 5 5

B). 10 10

C). 5 10

D). 10 5

What happens if you try to declare two variables with the same name but different cases?

A). Error

B). Both are declared

C). Only one is declared

D). None of the above

Can a function and a variable have the same name with different cases in JavaScript?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

How does JavaScript differentiate between 'myVar' and 'MyVar'?

A). It doesn't, both are the same

B). It treats them as different variables

C). It throws an error

D). None of the above

Which of the following statements is true about case sensitivity in JavaScript?

A). Variable names are case-insensitive

B). Function names are case-insensitive

C). Identifiers are case-sensitive

D). All of the above

Which of the following function names are considered identical in JavaScript?

A). myFunction and MyFunction

B). myfunction and myFunction

C). myFunction and myfunction

D). None of the above

How does JavaScript treat 'Function()' and 'function()'?

A). As the same function

B). As different functions

C). As a syntax error

D). As a reserved keyword

What is the significance of case sensitivity in JavaScript?

A). Enhances code readability

B). Reduces code size

C). Improves performance

D). Differentiates identifiers

Which of the following is a correct variable declaration in JavaScript?

A). var Variable = 1;

B). var variable = 1;

C). Both A and B

D). None of the above