Q
What is the output of console.log(innerVar); outside of exampleFunction if var innerVar = 'Hello'; is defined inside exampleFunction?

Answer & Solution

Answer: Option C
Solution:
Variables defined with var inside a function are not accessible outside of that function.
Related Questions on Average

Which of the following demonstrates lexical scoping?

A). Closure

B). Hoisting

C). Global scope

D). Local scope

What is block scope in JavaScript?

A). Variables scoped to a block

B). Variables scoped to a function

C). Variables scoped globally

D). Variables scoped locally

What is function scope in JavaScript?

A). Variables defined within a function

B). Variables defined outside a function

C). Variables defined within an object

D). Variables defined globally

What is the output of console.log(outerVar); outside of outerFunction if var outerVar = 'Outer'; is defined inside outerFunction?

A). Outer

B). undefined

C). Error

D). null

How do you declare a function-scoped variable using ES6?

A). var

B). let

C). const

D). function

Which keyword is used to declare a function-scoped variable?

A). var

B). let

C). const

D). function

How do you declare a block-scoped variable in ES6?

A). var

B). let

C). const

D). function

What happens to a function-scoped variable outside of its function?

A). It becomes a global variable

B). It becomes a local variable

C). It is accessible only within the function

D). It throws an error

How does lexical scoping affect nested functions in JavaScript?

A). Nested functions inherit variables from their outer functions

B). Nested functions have their own separate variables

C). Nested functions cannot access outer function variables

D). Nested functions create global variables

What happens if you declare a variable with the same name in both function and block scopes?

A). It creates two separate variables

B). It causes an error

C). It combines the scopes

D). It prioritizes the function scope