Q
How do you declare a function-scoped variable using ES6?

Answer & Solution

Answer: Option B
Solution:
In ES6, variables declared with let and const are also function-scoped.
Related Questions on Average

What happens to a function-scoped variable outside of its function?

A). It becomes a global variable

B). It becomes a local variable

C). It is accessible only within the function

D). It throws an error

What is the output of console.log(blockVar); outside of a block if let blockVar = 'Block'; is defined inside a block?

A). Block

B). undefined

C). Error

D). null

What is the output of console.log(outerVar); outside of outerFunction if var outerVar = 'Outer'; is defined inside outerFunction?

A). Outer

B). undefined

C). Error

D). null

What is function scope in JavaScript?

A). Variables defined within a function

B). Variables defined outside a function

C). Variables defined within an object

D). Variables defined globally

What is lexical scoping in JavaScript?

A). Variables scoped to the entire codebase

B). Variables scoped to their functions

C). Variables scoped based on their position in the code

D). Variables scoped based on their names

How can you access a variable declared in an inner block from an outer block?

A). Using the var keyword

B). Using the let keyword

C). Using the const keyword

D). Using the this keyword

Which of the following demonstrates lexical scoping?

A). Closure

B). Hoisting

C). Global scope

D). Local scope

Which keyword is used to declare a function-scoped variable?

A). var

B). let

C). const

D). function

What is hoisting in JavaScript?

A). Moving variables to the top of their function or global scope

B). Making variables undefined

C). Creating new variables

D). None of the above

Which of the following is true about function scope in JavaScript?

A). Variables are accessible globally

B). Variables are accessible only within their functions

C). Variables are accessible within an object

D). Variables are accessible everywhere in the code