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Q
What does the selector $('div > p') select in jQuery?

Answer & Solution

Answer: Option C
Solution:
$('div > p') selects all

elements that are direct children of

elements.
Related Questions on Average

How to select the element with the ID 'header' using jQuery?

A). $('#header').show();

B). $('header').select();

C). $('.header').show();

D). $('header').show();

How to select elements by their tag name using jQuery?

A). $('.tagname')

B). $('tagname')

C). $('element:tagname')

D). $('[tagname]')

How to select the first element within a set of matched elements using jQuery?

A). $('element:first')

B). $('element').first();

C). $('element').eq(0);

D). $('element').first();

How to select all elements with a specific class using jQuery?

A). $('.classname')

B). $('classname')

C). $('element.classname')

D). $('[classname]')

Which jQuery selector is used to target elements based on their position in a group of selected elements?

A). $('element:odd')

B). $('element:nth-child(odd)')

C). $('element:nth-of-type(odd)')

D). $('element:nth(odd)')

Which jQuery selector targets elements that are direct children of a specified parent element?

A). $('parent > child')

B). $('parent + child')

C). $('parent child')

D). $('parent ~ child')

How to select the first

  • element within a
      using jQuery?

      A). $('ul li').first();

      B). $('ul > li').first();

      C). $('li:first-child');

      D). $('ul').first().find('li');

  • How to select elements with a specific class using jQuery?

    A). $('classname')

    B). $('element.classname')

    C). $('.classname')

    D). $('[classname]')

    What does the selector $('ul > li') select in jQuery?

    A). All <ul> elements

    B). All <li> elements in the document

    C). All <li> elements that are direct children of <ul> elements

    D). All elements within <ul> elements

    How to select elements with a specific attribute and value using jQuery?

    A). $('[attribute=value]')

    B). $('attribute=value')

    C). $('element[attribute=value]')

    D). $('.attribute=value')