Q
How to select elements with a specific attribute using jQuery?

Answer & Solution

Answer: Option A
Solution:
$('[attribute]') selects all elements with a specific attribute.
Related Questions on Average

How to select the element with the ID 'header' using jQuery?

A). $('#header').show();

B). $('header').select();

C). $('.header').show();

D). $('header').show();

Which jQuery selector is used to select elements by their class?

A). .selectByClass('classname')

B). $('class:classname')

C). $('classname')

D). $('.classname')

How to select all <div> elements using jQuery?

A). $('div').addClass('selected');

B). document.querySelectorAll('div');

C). $(document).select('div');

D). $('div').find();

Which jQuery selector targets elements that are direct children of a specified parent element?

A). $('parent > child')

B). $('parent + child')

C). $('parent child')

D). $('parent ~ child')

How to select elements by their tag name using jQuery?

A). $('.tagname')

B). $('tagname')

C). $('element:tagname')

D). $('[tagname]')

What does the selector $('ul > li') select in jQuery?

A). All <ul> elements

B). All <li> elements in the document

C). All <li> elements that are direct children of <ul> elements

D). All elements within <ul> elements

What does the selector $('p.intro') select in jQuery?

A). All <p> elements with the class 'intro'

B). All <p> elements in the document

C). All elements with the class 'intro'

D). All elements with the tag name 'intro'

How to select the first

  • element within a
      using jQuery?

      A). $('ul li').first();

      B). $('ul > li').first();

      C). $('li:first-child');

      D). $('ul').first().find('li');

  • What does the selector $('div > p') select in jQuery?

    A). All <p> elements

    B). All <div> elements in the document

    C). All <p> elements that are direct children of <div> elements

    D). All <p> elements within <div> elements

    Which jQuery selector is used to target elements based on their position in a group of selected elements?

    A). $('element:odd')

    B). $('element:nth-child(odd)')

    C). $('element:nth-of-type(odd)')

    D). $('element:nth(odd)')