Q
How do you extract parts of a string and join them together in JavaScript?

Answer & Solution

Answer: Option A
Solution:
The .slice(start, end) method in JavaScript extracts a section of a string and returns it as a new string, optionally joining parts of the string together.
Related Questions on Average

How do you get the index of the first occurrence of a specified substring in a string?

A). string.indexOf(substring)

B). string.index(substring)

C). substring.positionIn(string)

D). string.search(substring)

What does the .toLowerCase() method do in JavaScript?

A). Converts all characters to lowercase

B). Converts all characters to uppercase

C). Trims leading and trailing whitespace

D). Converts string to a boolean

What is the result of 'Hello'.substring(0, 3) in JavaScript?

A). 'Hell'

B). 'Hello'

C). 'o'

D). 'llo'

What is the correct way to compare two strings in JavaScript for equality?

A). string1 == string2

B). string1.compare(string2)

C). string1.equals(string2)

D). string1 === string2

What is the result of 'apple'.charAt(2) in JavaScript?

A). 'p'

B). 'l'

C). 'a'

D). 'pp'

How do you concatenate two strings in JavaScript?

A). string1.concat(string2)

B). string1 + string2

C). string1.join(string2)

D). string1.combine(string2)

How do you find the length of a string in JavaScript?

A). string.length

B). string.size

C). string.length()

D). lengthOf(string)

How do you check if a string starts with a specific substring in JavaScript?

A). string.startsWith(substring)

B). string.startsWithWith(substring)

C). string.beginsWith(substring)

D). string.starts(substring)

What does the .replace() method do in JavaScript?

A). Replaces a specified value with another value

B). Removes a substring

C). Splits a string into an array

D). Joins two or more strings

How do you extract a part of a string and replace it with another substring in JavaScript?

A). string.replace(oldSubstring, newSubstring)

B). string.extractReplace(old, new)

C). string.modify(old, new)

D). string.substitute(old, new)