Q
How can you ensure variable immutability within a block?

Answer & Solution

Answer: Option C
Solution:
Variables declared with const are immutable within their block and cannot be reassigned.
Related Questions on Average

What is the main difference between var and let in terms of scope?

A). var is block-scoped, let is function-scoped

B). var is function-scoped, let is block-scoped

C). Both var and let are block-scoped

D). Both var and let are function-scoped

Which keyword introduces block-scoped variables in JavaScript?

A). var

B). let

C). const

D). function

Which of the following correctly defines a block scope?

A). A scope that encompasses the entire codebase

B). A scope that encompasses a function

C). A scope that encompasses a block of code delimited by curly braces

D). A scope that encompasses an object

What is the output of console.log(i); outside the loop if let i = 10; is declared inside a loop?

A). 10

B). undefined

C). Error

D). 0

How can you access a variable declared in an inner block from an outer block?

A). Using the var keyword

B). Using the let keyword

C). Using the const keyword

D). Using the this keyword

How does block scope affect the visibility of variables in nested blocks?

A). Variables are only visible within their immediate block

B). Variables are visible within all nested blocks

C). Variables are only visible within functions

D). Variables are globally visible

How does block scope help prevent variable hoisting issues?

A). By moving variables to the top of the code

B). By restricting variables to their block

C). By making variables accessible globally

D). By assigning default values to variables

What is the output of console.log(blockVar); outside a block if let blockVar = 'Block'; is declared inside a block?

A). Block

B). undefined

C). Error

D). null

What is lexical scoping in JavaScript?

A). Variables scoped to the entire codebase

B). Variables scoped to their functions

C). Variables scoped based on their position in the code

D). Variables scoped based on their names

What is the output of console.log(innerVar); outside exampleFunction if let innerVar = 'Hello'; is declared inside exampleFunction?

A). Hello

B). undefined

C). Error

D). null