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1.
The solution of equation 
lies in the interval
lies in the interval
2.
The circular wire of diameter 10 cm is cut and placed along the circumference of a circle of diameter 1 m. The angle subtended by the wire at the center of the circle is equal to
3.
If 
, then 
is equal to
, then is equal to
4.
5.
The equation 
has
has
6.
In a triangle 
7.
is equal to
is equal to
8.
If 
and 
, then 
is equal to
and , then is equal to
9.
If in a 
then the value of 
is
then the value of is
10.
If 
are respectively the perpendiculars from the vertices of a triangle to the opposite sides, then 
is equal to
are respectively the perpendiculars from the vertices of a triangle to the opposite sides, then is equal to