Q
What does the fail() method do in jQuery promises?

Answer & Solution

Answer: Option A
Solution:
The fail() method attaches a callback that is executed when the promise is rejected, handling errors in asynchronous operations.
Related Questions on Average

How can you reject a deferred object in jQuery?

A). Using the reject() method

B). Using the resolve() method

C). Using the done() method

D). Using the always() method

What is event delegation in jQuery?

A). Attaching event handlers to dynamically created elements

B). Attaching event handlers to static elements

C). Attaching event handlers to parent elements

D). Attaching event handlers to all elements

How can you create a promise from a deferred object in jQuery?

A). Using the promise() method

B). Using the then() method

C). Using the done() method

D). Using the fail() method

How can event delegation improve performance?

A). By reducing the number of event handlers

B). By increasing the number of event handlers

C). By attaching handlers directly to elements

D). By using inline event handlers

What does the promise() method return in jQuery?

A). A new deferred object

B). A new promise object

C). A new callback function

D). A new event handler

Which jQuery method is used to handle both success and failure cases of a promise?

A). done()

B). fail()

C). always()

D). then()

What is the purpose of the done() method in jQuery promises?

A). To handle failed operations

B). To handle completed operations

C). To handle pending operations

D). To create a new deferred object

Which method allows you to specify a callback that is executed regardless of the promise's outcome?

A). done()

B). fail()

C). always()

D). then()

How can you ensure that a callback runs only once, even if the promise is resolved multiple times?

A). Using the done() method

B). Using the fail() method

C). Using the once() method

D). Using the then() method

Which jQuery method is used to chain multiple asynchronous operations?

A). done()

B). fail()

C). then()

D). always()