Q
What does the $.each() method do in jQuery?

Answer & Solution

Answer: Option A
Solution:
The $.each() method iterates over a jQuery object, executing a function for each matched element.
Related Questions on Average

Which method is used to extend jQuery's functionality by adding a plugin?

A). $.fn.extend()

B). $.fn.add()

C). $.fn.plugin()

D). $.fn.new()

Which jQuery method is used to apply a plugin to selected elements?

A). $(selector).pluginName()

B). $(selector).usePlugin()

C). $(selector).applyPlugin()

D). $(selector).newPlugin()

How can you hide an element using a jQuery plugin?

A). this.hide()

B). this.visible(false)

C). this.remove()

D). this.display('none')

How do you ensure a jQuery plugin supports method chaining?

A). Return this

B). Use $.fn.chain

C). Call the chain() method

D). Use return false

What is the primary purpose of jQuery plugins?

A). Extend jQuery's prototype object

B). Simplify HTML documents

C). Manage CSS styles

D). Enhance server-side scripting

How can you extend an existing jQuery plugin with new methods?

A). $.fn.pluginName.newMethod = function()

B). $.pluginName.extend()

C). $.fn.extend(pluginName, newMethod)

D). $.extend(pluginName, newMethod)

How can you pass options to a jQuery plugin?

A). As an object

B). As a string

C). As an array

D). As a number

How do you provide default settings for a jQuery plugin?

A). Using $.extend()

B). Using $.defaults()

C). Using $.settings()

D). Using $.config()

How can you ensure a jQuery plugin does not conflict with other libraries?

A). Use noConflict()

B). Use unique variable names

C). Avoid global variables

D). Use namespaces

What is the purpose of using the $.fn object in jQuery plugins?

A). To access jQuery prototype

B). To access the DOM directly

C). To handle events

D). To create HTML elements