Q
How can you prevent the default form submission behavior using jQuery?

Answer & Solution

Answer: Option A
Solution:
The event.preventDefault() method prevents the default form submission behavior in jQuery by preventing the form from being submitted normally.
Related Questions on Average

What method in jQuery is commonly used to handle AJAX requests?

A). A. $.ajax()

B). B. $.submit()

C). C. $.click()

D). D. $.toggle()

How does AJAX content loading differ from traditional page navigation?

A). A. It requires server restart

B). B. It allows for partial updates

C). C. It only works with JSON data

D). D. It doesn't support HTTPS

Which method is used to serialize form data for AJAX submission in jQuery?

A). A. $.serialize()

B). B. $.post()

C). C. $.get()

D). D. $.load()

What is the purpose of AJAX-based content loading?

A). A. To improve website security

B). B. To reduce server load

C). C. To simplify HTML structure

D). D. To enhance user experience

Which option in $.ajax() is used to specify the expected data type of the server response?

A). A. dataType

B). B. contentType

C). C. responseType

D). D. data

How does AJAX-based content loading contribute to better user experience?

A). A. By increasing page load times

B). B. By reducing server load

C). C. By enabling partial updates

D). D. By encrypting server responses

How can you handle a successful AJAX response in jQuery?

A). A. Using the fail option

B). B. Using the success option

C). C. Using the error option

D). D. Using the complete option

What is the primary benefit of AJAX form submission?

A). A. Enhanced server security

B). B. Improved user experience

C). C. Faster loading times

D). D. Reduced browser compatibility

How do you handle successful AJAX responses using jQuery?

A). A. Using the done option

B). B. Using the complete option

C). C. Using the success option

D). D. Using the error option

Which jQuery method is commonly used to perform an AJAX GET request?

A). A. $.post()

B). B. $.get()

C). C. $.submit()

D). D. $.serialize()